Поменять значение в XML

Требуется поменять значение, спрятанное глубоко в XML.

<smev:RequestIdRef>{219F416E-4DB7-43DA-AFED-2EFFDD67C32A}</smev:RequestIdRef>

import org.apache.xpath.XPathAPI;

...



String respBody = "....";// XML
Element root = getXmlRoot(respBody);
Node requestIdRefNode = getXPath(root, "//*[local-name() = 'RequestIdRef']");
requestIdRefNode.setTextContent("New value");

public static final Element getXmlRoot(String xmlData) throws Exception
{
        // logger.info("Trying get root from: " + xmlData);
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        factory.setNamespaceAware(true);
        DocumentBuilder builder = factory.newDocumentBuilder();
        return builder.parse(new InputSource(new StringReader(xmlData))).getDocumentElement();
}

public static final Node getXPath(Element xmlData, String path) throws Exception

{
       Node nodes = null;    
       nodes = XPathAPI.selectSingleNode(xmlData,
                                 String.format("%s", path));
       return nodes;
 } 

Альтернативный способ, без использование XPathAPI:

    public static Document getXMLDocument(String xmlSource) throws Exception
    {
        DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = domFactory.newDocumentBuilder();
        return builder.parse(new InputSource(new StringReader(xmlSource)));
    }
 

    public static Node getXMLTagContent(Document document, String nodeExpression) throws XPathExpressionException
    {
        Node node = null;
        XPathFactory factory = XPathFactory.newInstance();
        XPath xpath = factory.newXPath();
        XPathExpression expression = xpath.compile(nodeExpression);
        if (document != null)
            node = (Node) expression.evaluate(document, XPathConstants.NODE);
        return node;
    }